Sizing guide · Start here
Reviewed by the Suyog Hydrosystems engineering team · Updated 12 Aug 2026 · ~8 min read
Selecting a hydraulic power pack is a chain of decisions, each feeding the next: what the machine has to do sets the force, force and bore set the pressure, the speed you need sets the flow, and pressure and flow together set the motor. Get the order right and the unit almost specifies itself. This guide walks the full method an engineer follows, with a worked example carried the whole way through. It is general engineering guidance; Suyog-specific specifications are called out separately where they appear.
Work through these seven steps in order. Each one produces a number that the next step needs, so resist the temptation to jump ahead to "which pump" before the application is nailed down.
Before any calculation, describe the job in plain terms. What does the machine physically do — clamp, press, lift, tilt, bend, feed, hold? A power pack that opens and closes a clamp for a few seconds every cycle is a very different animal from one that holds a press under load all shift.
Pin down these points:
Everything downstream depends on this description. A machine with three clamps that fire one after another needs enough flow for one clamp; the same three clamping at once needs three times the flow.
Pressure is set by the force you need and the piston area it acts on. A cylinder develops force according to:
F = P × A where Abore = π/4 × D²
Rearranged, the pressure needed to make a given force on a chosen bore is P = F ÷ A. Keep the units straight: with force in newtons and area in mm², pressure in bar is P (bar) = 10 × F (N) ÷ A (mm²), because 1 bar = 0.1 N/mm².
Suppose the application from step 1 needs a clamping force of 5 tonne and you have chosen an 80 mm bore cylinder.
That is the pressure to just make the force — you never design to it. Add a working margin of roughly 20% for seal friction, pressure drop in the lines and a little reserve, giving about 117 bar, then round up to a standard figure. A 120 bar working pressure is the sensible specification here. Choosing a larger bore would lower the required pressure; a smaller bore would raise it. This is the trade-off behind every cylinder-and-pressure pairing.
Rule of thumb: size the working pressure at required pressure + ~20% margin, then round up to a standard rating your pump, valves and gauge all share.
Pressure makes the force; flow makes the speed. The rate at which oil enters the cylinder sets how fast the piston moves:
v = Q ÷ A • Q = Vg × n ÷ 1000
The first equation gives cylinder speed v from flow Q and bore area A. The second gives the flow a fixed-displacement pump delivers, from its displacement Vg (cc/rev) and drive speed n (rpm) — the same relationship used in our flow calculator (which also applies volumetric efficiency).
Say the clamp must close at about 50 mm/s. Using the 80 mm bore (A = 5,027 mm²) from step 2:
Now pick a pump to deliver 15 L/min. At a typical 1,440 rpm motor speed, the displacement needed is roughly Vg = Q × 1000 ÷ n = 15 × 1000 ÷ 1440 ≈ 10.4 cc/rev. An 11 cc/rev gear pump is the nearest standard size and delivers about 15 L/min after volumetric losses. If several actuators move at once, add their individual flows before selecting the pump.
With working pressure and flow both known, the motor follows directly. The drive power is:
Motor kW = (P [bar] × Q [L/min]) ÷ (600 × η) η ≈ 0.85
The efficiency η covers pump and drive losses; 0.85 is a reasonable working figure. This is the same expression behind our motor power calculator.
Carrying the running numbers through:
Always round up to the next standard motor size — the common frame ratings are 0.75, 1.1, 1.5, 2.2, 3.7, 5.5 and 7.5 kW. So 3.53 kW selects a 3.7 kW motor. Size the motor for the highest simultaneous pressure-and-flow demand in the cycle, not the average, or the motor will trip on the peak.
| Quantity | Value in the worked example |
|---|---|
| Required force | 5 tonne (≈ 49 kN) |
| Cylinder bore | 80 mm |
| Working pressure (with margin) | ~120 bar |
| Cylinder speed target | ~50 mm/s |
| Pump flow | ~15 L/min (11 cc/rev @ 1440 rpm) |
| Motor power | 3.7 kW (from 3.53 kW calculated) |
| Reservoir (next step) | 45–75 L |
The reservoir does more than hold oil: it lets air and contamination settle out, sheds heat, and gives the pump a settled supply. The long-standing rule of thumb sizes it at 3 to 5 times the pump flow per minute:
Tank (L) = k × Q [L/min] ( k = 3 to 5 )
For our 15 L/min pump that is a 45 to 75 litre tank. Use the lower end (3×) for intermittent, space-constrained duty; use the upper end (5×) for continuous running, where the extra volume keeps the oil cooler and gives entrained air time to release. When duty is heavy and space is tight, add a cooler rather than starving the tank — an undersized reservoir is one of the most common causes of an HPU that overheats in service. See Hydraulic Tank Sizing for the full treatment.
The manifold is where the unit becomes a controllable machine rather than just a pump on a tank. At minimum, specify:
The last step covers the practical constraints that decide whether a sound calculation survives in the real installation.
Put the method to work
Run your own numbers, get a full recommended configuration, browse standard units, or send us the application and let our engineers confirm it.
Start from the force the machine must produce and the cylinder bore you plan to use. Pressure equals force divided by piston area (P = F ÷ A, with A = π/4 × D²). Calculate the pressure needed to make the force on that bore, then add roughly 20% as a working margin and round up to a standard pressure the pump and valves are rated for. A 5 tonne clamp on an 80 mm bore needs about 98 bar, so a ~120 bar working pressure is a sensible specification.
Motor power in kW = (working pressure in bar × flow in L/min) ÷ (600 × overall efficiency), taking efficiency at about 0.85. Work out the figure at your peak pressure and flow, then round up to the next standard motor size — 0.75, 1.1, 1.5, 2.2, 3.7, 5.5 or 7.5 kW. For 120 bar and 15 L/min the calculation gives about 3.5 kW, so a 3.7 kW motor is selected.
The common rule of thumb is 3 to 5 times the pump flow per minute. A 15 L/min pump therefore wants a 45 to 75 litre tank. Use the lower end for intermittent duty where space is tight and the upper end for continuous running, where the extra volume helps the oil cool and release entrained air. If the duty cycle is heavy, size the tank generously or add a cooler rather than undersizing.
Below roughly 2.2 kW a single-phase supply can work for light or intermittent duty, and it suits small stand-alone or mobile units. From about 2.2 kW upward, and for any continuous industrial duty, three-phase is strongly preferred — it runs cooler, starts more reliably under load and is the norm on factory floors. Confirm the available supply before finalising the motor.
How displacement and speed set your flow — and cylinder speed.
Read guide →Turning working pressure and flow into the right motor kW.
Read guide →Why reservoir volume drives cooling, air release and oil life.
Read guide →The two variables that decide force and speed — and why they're independent.
Read guide →